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    <title>测试附件</title>
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    <description><![CDATA[<p>我晚上</p>
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<p>&nbsp;</p>]]></description>
    <pubDate>Fri, 05 Sep 2025 12:21:57 +0800</pubDate>
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    <title>On the left is the graph</title>
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<p>On the left is the graph of&nbsp;Ueff(r)&nbsp;for some non-zero value of&nbsp;L. This picture is incredibly useful, because you can understand what's going to happen to a mass that's moving in this potential just imagining that it's a&nbsp;<em>hill</em>&nbsp;that the particle is sliding along.</p>
<p>The shape of the orbit will depend on the energy, represented by the horizontal dashed line. When the energy is at the minimum of the effective potential, the particle will just sit there at the bottom of the hill! That means that&nbsp;r&nbsp;is&nbsp;<em>constant</em>. The planet isn't sitting still&mdash;remember that it has angular momentum&nbsp;L=mr2&theta;˙, and so the&nbsp;<em>angular</em>&nbsp;coordinate is changing. So when the energy is at the minimum of the effective potential, the planet will orbit the star in a circle!</p>
<p align="center" data-preserve-html-node="true"><img src="https://www.physicswithelliot.com/s/ellipse-orbit.png" width="600" data-preserve-html-node="true"></p>
<p align="center" data-preserve-html-node="true">&nbsp;</p>
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    <pubDate>Fri, 05 Sep 2025 12:17:29 +0800</pubDate>
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    <title>English Article2</title>
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    <pubDate>Thu, 04 Sep 2025 16:08:52 +0800</pubDate>
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    <pubDate>Thu, 04 Sep 2025 08:15:21 +0800</pubDate>
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    <title>English Article</title>
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    <pubDate>Thu, 04 Sep 2025 08:14:49 +0800</pubDate>
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